What is the inverse of f(x)=4\sqrt[3]{1/3 (x-5)}+2 ?

The inverse of f(x)=4\sqrt[3]{1/3 (x-5)}+2 is 37/8+(3x^3)/(64)-(9x^2)/(32)+(9x)/(16)

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inverse of f(x)=4\sqrt[3]{1/3 (x-5)}+2

inverse

\frac{37}{8} + \frac{3 x ^{3}}{64} - \frac{9 x ^{2}}{32} + \frac{9 x}{16}

Solution steps

Replace

x

with

y

Solve for

\frac{37}{8} + \frac{3 x ^{3}}{64} - \frac{9 x ^{2}}{32} + \frac{9 x}{16}

\frac{1}{4} x^{3} - 2

f (x) = - 9 x + 45

f (x) = 2 y + 4 x = 7

f (x) = \frac{3 x + 6}{x - 1}

y = lo g_{2} (x)

What is the inverse of f(x)=4\sqrt[3]{1/3 (x-5)}+2 ?
The inverse of f(x)=4\sqrt[3]{1/3 (x-5)}+2 is 37/8+(3x^3)/(64)-(9x^2)/(32)+(9x)/(16)