What is the domain of f(x)=(3x^2+1)/((x-1)^2) ?

The domain of f(x)=(3x^2+1)/((x-1)^2) is x 1

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domain of f(x)=(3x^2+1)/((x-1)^2)

domain

f (x) = \frac{3 x ^{2} + 1}{( x - 1 ) ^{2}}

x < 1 or x > 1

Interval Notation

(- \infty, 1) \cup (1, \infty)

Solution steps

Find undefined (singularity) points:

x = 1

The function domain

x < 1 or x > 1

f (x) = \frac{( 2 z - 6 )}{9 z + 1}

u (x) = x + 1

f (x) = 6 x + 6

6 x + 3 y = - 9

3 - 2 x

What is the domain of f(x)=(3x^2+1)/((x-1)^2) ?
The domain of f(x)=(3x^2+1)/((x-1)^2) is x<1\lor x>1