What is the domain of f(x)=((sqrt(x-4))(x-8))/(x-5) ?

The domain of f(x)=((sqrt(x-4))(x-8))/(x-5) is 4 5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of f(x)=((sqrt(x-4))(x-8))/(x-5)

domain

f (x) = \frac{( x - 4 ) ( x - 8 )}{x - 5}

4 \leq x < 5 or x > 5

Interval Notation

[4, 5) \cup (5, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 4

Find undefined (singularity) points:

x = 5

Combine real regions and undefined points for final function domain

4 \leq x < 5 or x > 5

f (x) = \frac{- 2 x + 1}{3}

f (x) = 4^{x - 2}

f (x) = 2 - 2 x + 1

f (x) = \frac{x}{x ^{2} - 36}

f (x) = \frac{3}{4} x + 9

What is the domain of f(x)=((sqrt(x-4))(x-8))/(x-5) ?
The domain of f(x)=((sqrt(x-4))(x-8))/(x-5) is 4<= x<5\lor x>5