What is the extreme f(x)=-0.3x^2+2.4x+98.6 ?

The extreme f(x)=-0.3x^2+2.4x+98.6 is Maximum(4,103.4)

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extreme f(x)=-0.3x^2+2.4x+98.6

extreme points

f (x) = - 0.3 x^{2} + 2.4 x + 98.6

Maximum (4, 103.4)

Solution steps

f^{'} (x) = - 0.6 x + 2.4

Find intervals:

Increasing

: - \infty < x < 4,

Decreasing

: 4 < x < \infty

Plug

x = 4

into

- 0.3 x^{2} + 2.4 x + 98.6 : 103.4

Maximum (4, 103.4)

f (x) = \frac{9 - 3 x}{x - 10}

y = \frac{x ^{9}}{81 - x ^{2}}

(- 3.8) (1.5)

y = - x^{2} - 5

f (x) = x^{4} - 98 x^{2} + 2401

What is the extreme f(x)=-0.3x^2+2.4x+98.6 ?
The extreme f(x)=-0.3x^2+2.4x+98.6 is Maximum(4,103.4)