What is the domain of (x^3)/(x^2-9) ?

The domain of (x^3)/(x^2-9) is x 3

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domain of (x^3)/(x^2-9)

domain

\frac{x ^{3}}{x ^{2} - 9}

x < - 3 or - 3 < x < 3 or x > 3

Interval Notation

(- \infty, - 3) \cup (- 3, 3) \cup (3, \infty)

Solution steps

Find undefined (singularity) points:

x = 3, x = - 3

The function domain

x < - 3 or - 3 < x < 3 or x > 3

f (x) = 2 \cdot x + 1

f (x) = x^{2} + 16

4 x - 1 + 5

f (x) = - x^{3} + 6 x^{2} - 2

What is the domain of (x^3)/(x^2-9) ?
The domain of (x^3)/(x^2-9) is x<-3\lor-3<x<3\lor x>3