What is the asymptotes of f(x)=(2x^2+1)/(3x^2-5) ?

The asymptotes of f(x)=(2x^2+1)/(3x^2-5) is Vertical: x=-sqrt(5/3),x=sqrt(5/3),Horizontal: y= 2/3

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asymptotes of f(x)=(2x^2+1)/(3x^2-5)

asymptotes

f (x) = \frac{2 x ^{2} + 1}{3 x ^{2} - 5}

Vertical : x = - \frac{5}{3}, x = \frac{5}{3}, Horizontal : y = \frac{2}{3}

Solution steps

Vertical asymptotes of

\frac{2 x ^{2} + 1}{3 x ^{2} - 5} : x = - \frac{5}{3}, x = \frac{5}{3}

Horizontal Asymptotes of

\frac{2 x ^{2} + 1}{3 x ^{2} - 5} : y = \frac{2}{3}

Slant Asymptotes of

\frac{2 x ^{2} + 1}{3 x ^{2} - 5} :

None

Vertical : x = - \frac{5}{3}, x = \frac{5}{3}, Horizontal : y = \frac{2}{3}

- 2 x^{2} + 12 x - 14

f (x) = 2 - 3 x^{2} - x^{3}

f (x) = x e^{- 3 x}

f (x) = 121 - x^{2}

f (x) = \frac{x ^{3}}{x ^{2} - 4}

What is the asymptotes of f(x)=(2x^2+1)/(3x^2-5) ?
The asymptotes of f(x)=(2x^2+1)/(3x^2-5) is Vertical: x=-sqrt(5/3),x=sqrt(5/3),Horizontal: y= 2/3