What is the asymptotes of f(x)=(x^3-1)/(x^2-9) ?

The asymptotes of f(x)=(x^3-1)/(x^2-9) is Vertical: x=-3,x=3,Slant: y=x

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asymptotes of f(x)=(x^3-1)/(x^2-9)

asymptotes

f (x) = \frac{x ^{3} - 1}{x ^{2} - 9}

Vertical : x = - 3, x = 3, Slant : y = x

Solution steps

Vertical asymptotes of

\frac{x ^{3} - 1}{x ^{2} - 9} : x = - 3, x = 3

Horizontal Asymptotes of

\frac{x ^{3} - 1}{x ^{2} - 9} :

None

Slant Asymptotes of

\frac{x ^{3} - 1}{x ^{2} - 9} : y = x

Vertical : x = - 3, x = 3, Slant : y = x

\frac{x ^{2} + 4 x + 7}{x + 3}

- 4 cos (\frac{1}{3} x)

f (x) = \frac{x + 4}{2 x}

y = x + 2

\frac{5 ( x ^{2} - 1 )}{x ^{2} - 4}

What is the asymptotes of f(x)=(x^3-1)/(x^2-9) ?
The asymptotes of f(x)=(x^3-1)/(x^2-9) is Vertical: x=-3,x=3,Slant: y=x