What is the domain of f(x)=sqrt(x^2-7x+10) ?

The domain of f(x)=sqrt(x^2-7x+10) is x = 5

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domain of f(x)=sqrt(x^2-7x+10)

domain

f (x) = x^{2} - 7 x + 10

x \leq 2 or x \geq 5

Interval Notation

(- \infty, 2] \cup [5, \infty)

Solution steps

Find non-negative values for radicals:

x \leq 2 or x \geq 5

The function domain

x \leq 2 or x \geq 5

(- 1, - 5), (5, - 3)

f (x) = - x + 5

x^{4} + 1

f (x) = 2 x + 3 y = 12

y = 4 x^{2} - 4

What is the domain of f(x)=sqrt(x^2-7x+10) ?
The domain of f(x)=sqrt(x^2-7x+10) is x<= 2\lor x>= 5