What is the range of f(x)=sqrt(2x-1) ?

The range of f(x)=sqrt(2x-1) is f(x)>= 0

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range of f(x)=sqrt(2x-1)

range

f (x) = 2 x - 1

f (x) \geq 0

Interval Notation

[0, \infty)

Solution steps

The range of an radical function of the form

c a x + b + k

f (x) \geq k

k = 0

f (x) \geq 0

f (x) = (3 x - 7)^{3}

(3.1) (7.8)

f (x) = (x \frac{1}{2} + 2)^{5} - 10

(x^{2} + 1)^{2}

\frac{5 x}{9 x - 1}