What is the monotone x/(x^2-1) ?

The monotone x/(x^2-1) is Decreasing:-infinity <x<-1,Decreasing:-1<x<1,Decreasing:1<x<infinity

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monotone x/(x^2-1)

monotone intervals

\frac{x}{x ^{2} - 1}

Decreasing : - \infty < x < - 1, Decreasing : - 1 < x < 1, Decreasing : 1 < x < \infty

Solution steps

f^{'} (x) = \frac{- x ^{2} - 1}{( x ^{2} - 1 ) ^{2}}

Find intervals:

Decreasing

: - \infty < x < - 1,

Decreasing

: - 1 < x < 1,

Decreasing

: 1 < x < \infty

Decreasing : - \infty < x < - 1, Decreasing : - 1 < x < 1, Decreasing : 1 < x < \infty

f (x) = x^{2} + 2

f (x) = \frac{1}{x ^{2} - x}

y = - 2 x + 1

(- 6.6) - \frac{1}{4}

(2, - 1), (4, - 5)

What is the monotone x/(x^2-1) ?
The monotone x/(x^2-1) is Decreasing:-infinity <x<-1,Decreasing:-1<x<1,Decreasing:1<x<infinity