What is the critical ((x-1))/(x^2+3) ?

The critical ((x-1))/(x^2+3) is x=-1,x=3

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critical ((x-1))/(x^2+3)

critical points

\frac{( x - 1 )}{x ^{2} + 3}

x = - 1, x = 3

Solution steps

\frac{x - 1}{x ^{2} + 3}

Find where

f^{'} (x)

is equal to zero or undefined

x = - 1, x = 3

Identify critical points not in

f (x)

domain

Domain of

\frac{x - 1}{x ^{2} + 3} : - \infty < x < \infty

All critical points are in domain

x = - 1, x = 3

3 cos (x)

(x - 6)^{3}

\frac{1}{x ^{2}}

f (x) = \frac{3}{x + 2}

\frac{x - 1}{x + 7}