What is the critical f(x)=-16x^2+30x+3 ?

The critical f(x)=-16x^2+30x+3 is x= 15/16

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critical f(x)=-16x^2+30x+3

critical points

f (x) = - 16 x^{2} + 30 x + 3

x = \frac{15}{16}

Solution steps

- 16 x^{2} + 30 x + 3

Find where

f^{'} (x)

is equal to zero or undefined

x = \frac{15}{16}

Identify critical points not in

f (x)

domain

Domain of

- 16 x^{2} + 30 x + 3 : - \infty < x < \infty

All critical points are in domain

x = \frac{15}{16}

f (x) = (x + 2)^{3} + 6

f (x) = 2 x - 2

y = 2 x^{2} - 8 x + 6

(1) (1.2)

\frac{x - 4}{x - 11}

What is the critical f(x)=-16x^2+30x+3 ?
The critical f(x)=-16x^2+30x+3 is x= 15/16