What is the critical 14cos(θ)+7sin^2(θ) ?

The critical 14cos(θ)+7sin^2(θ) is θ=2pin,θ=pi+2pin

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critical 14cos(θ)+7sin^2(θ)

critical points

14 cos (θ) + 7 sin^{2} (θ)

θ = 2 πn, θ = π + 2 πn

Solution steps

14 cos (θ) + 7 sin^{2} (θ)

Find where

f^{'} (θ)

is equal to zero or undefined

θ = 2 πn, θ = π + 2 πn

Identify critical points not in

f (θ)

domain

Domain of

14 cos (θ) + 7 sin^{2} (θ) : - \infty < θ < \infty

All critical points are in domain

θ = 2 πn, θ = π + 2 πn

3 x + 5 y = - 5

\frac{3 x}{2 - x}

f (x) = x^{2} - 8 x

x^{2} - 16

(0, 0), (0.15, 1.9621)

What is the critical 14cos(θ)+7sin^2(θ) ?
The critical 14cos(θ)+7sin^2(θ) is θ=2pin,θ=pi+2pin