What is the inverse of f(x)=(2-(1-3x))/((2x-5)) ?

The inverse of f(x)=(2-(1-3x))/((2x-5)) is (1+5x)/(2x-3)

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inverse of f(x)=(2-(1-3x))/((2x-5))

inverse

f (x) = \frac{2 - ( 1 - 3 x )}{( 2 x - 5 )}

\frac{1 + 5 x}{2 x - 3}

Solution steps

y = \frac{2 - ( 1 - 3 x )}{2 x - 5}

Replace

x

with

y

x = \frac{2 - ( 1 - 3 y )}{2 y - 5}

Solve for

y, x = \frac{2 - ( 1 - 3 y )}{2 y - 5}

\frac{1 + 5 x}{2 x - 3}

\frac{1}{x ^{2} + 1}

- 6 sin (3 x + \frac{π}{2})

x^{2} - 2 x - 8

f (x) = 16 x^{5} - 12 x^{3} + 4 x^{2} - 3

f (x) = \frac{x}{8} - 3

What is the inverse of f(x)=(2-(1-3x))/((2x-5)) ?
The inverse of f(x)=(2-(1-3x))/((2x-5)) is (1+5x)/(2x-3)