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Popular >

f(x)=x^2-5x+6

Solution

f (x) = x^{2} - 5 x + 6

Solution

Domain : - \infty < x < \infty

Range : f (x) \geq - \frac{1}{4}

X Intercepts : (3, 0), (2, 0), Y Intercepts : (0, 6)

Vertex : Minimum (\frac{5}{2}, - \frac{1}{4})

Inverse : \frac{5 + 4 x + 1}{2}, \frac{5 - 4 x + 1}{2}

+1

Interval Notation

Domain : (- \infty, \infty)

Range : [- \frac{1}{4}, \infty)

Solution steps

Domain of

x^{2} - 5 x + 6 : - \infty < x < \infty

Range of

x^{2} - 5 x + 6 : f (x) \geq - \frac{1}{4}

Axis interception points of

x^{2} - 5 x + 6 :

X Intercepts

: (3, 0), (2, 0),

Y Intercepts

: (0, 6)

Vertex of

x^{2} - 5 x + 6 :

Minimum

(\frac{5}{2}, - \frac{1}{4})

Inverse of

x^{2} - 5 x + 6 : \frac{5 + 4 x + 1}{2}, \frac{5 - 4 x + 1}{2}

Popular Examples

inflection (e^x-e^{-x})/9 inflection points

\frac{e ^{x} - e ^{- x}}{9}

asymptotes of f(x)=(-3x+15)/(x^2-5x)asymptotes

f (x) = \frac{- 3 x + 15}{x ^{2} - 5 x}

slope ofintercept x+2y=10 slope intercept

x + 2 y = 10

slope of (2(-1)-3)/(2(-1)+5)slope

\frac{2 ( - 1 ) - 3}{2 ( - 1 ) + 5}

monotone f(x)= 1/3 x^3-3/x x^2 monotone intervals

f (x) = \frac{1}{3} x^{3} - \frac{3}{x} x^{2}

Frequently Asked Questions (FAQ)

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