What is the critical x/((x^2-1)^{1/3)} ?

The critical x/((x^2-1)^{1/3)} is x=-sqrt(3),x=sqrt(3)

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critical x/((x^2-1)^{1/3)}

critical points

\frac{x}{( x ^{2} - 1 ) ^{\frac{1}{3}}}

x = - 3, x = 3

Solution steps

\frac{x}{( x ^{2} - 1 ) ^{\frac{1}{3}}}

Find where

f^{'} (x)

is equal to zero or undefined

x = - 3, x = 3, x = - 1, x = 1

Identify critical points not in

f (x)

domain

Domain of

\frac{x}{( x ^{2} - 1 ) ^{\frac{1}{3}}} : x < - 1 or - 1 < x < 1 or x > 1

\frac{x}{( x ^{2} - 1 ) ^{\frac{1}{3}}}

is not defined at

x = - 1, x = 1

, therefore:

x = - 3, x = 3

f (x) = \frac{x + 1}{( x + 4 ) ( x - 6 )}

f (x) = \frac{1}{2} cos (x)

f (x) = 2 (x - 4)

f (x) = \frac{1}{7 x}

f (x) = 9 x + 36

What is the critical x/((x^2-1)^{1/3)} ?
The critical x/((x^2-1)^{1/3)} is x=-sqrt(3),x=sqrt(3)