What is the asymptotes of f(x)=((x^2+1))/(x+1) ?

The asymptotes of f(x)=((x^2+1))/(x+1) is Vertical: x=-1,Slant: y=x-1

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asymptotes of f(x)=((x^2+1))/(x+1)

asymptotes

f (x) = \frac{( x ^{2} + 1 )}{x + 1}

Vertical : x = - 1, Slant : y = x - 1

Solution steps

Vertical asymptotes of

\frac{x ^{2} + 1}{x + 1} : x = - 1

Horizontal Asymptotes of

\frac{x ^{2} + 1}{x + 1} :

None

Slant Asymptotes of

\frac{x ^{2} + 1}{x + 1} : y = x - 1

Vertical : x = - 1, Slant : y = x - 1

4 x^{2} - x - 3

f (x) = 65 x - 10

f (x) = \frac{9 + 4 x ^{2}}{2 x ^{2}}

y = cos (4 x) + 1

f (x) = 6^{x} + 3

What is the asymptotes of f(x)=((x^2+1))/(x+1) ?
The asymptotes of f(x)=((x^2+1))/(x+1) is Vertical: x=-1,Slant: y=x-1