What is the critical f(x)=x^{5/2}-5x^2 ?

The critical f(x)=x^{5/2}-5x^2 is x=0,x=16

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critical f(x)=x^{5/2}-5x^2

critical points

f (x) = x^{\frac{5}{2}} - 5 x^{2}

x = 0, x = 16

Solution steps

x^{\frac{5}{2}} - 5 x^{2}

Find where

f^{'} (x)

is equal to zero or undefined

x = 0, x = 16

Identify critical points not in

f (x)

domain

Domain of

x^{\frac{5}{2}} - 5 x^{2} : x \geq 0

All critical points are in domain

x = 0, x = 16

f (x) = x^{3} - x^{2} - 2 x

f = \frac{8}{5}

f (x) = \frac{x}{x - 2}

f (x) = 15 - (\frac{x}{8.345})

f (x) = x^{2} - 12 x + 36

What is the critical f(x)=x^{5/2}-5x^2 ?
The critical f(x)=x^{5/2}-5x^2 is x=0,x=16