What is the range of (x-8)/(x+7) ?

The range of (x-8)/(x+7) is f(x) 1

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range of (x-8)/(x+7)

range

\frac{x - 8}{x + 7}

f (x) < 1 or f (x) > 1

Interval Notation

(- \infty, 1) \cup (1, \infty)

Solution steps

The function range is the combined domain of the inverse functions

Find the inverse function(s) of:

\frac{x - 8}{x + 7}

Inverse of

\frac{x - 8}{x + 7} : \frac{- 8 - 7 x}{x - 1}

\frac{- 8 - 7 x}{x - 1}

Find the domain of each inverse function

Domain of

\frac{- 8 - 7 x}{x - 1} : x < 1 or x > 1

Combine the intervals

f (x) < 1 or f (x) > 1

lo g_{3} (x)

y = x^{3} - 12 x

3 x - 5

(11, - 2), (2, - 3)

f (x) = 2 x^{2} - 5 x + 1

What is the range of (x-8)/(x+7) ?
The range of (x-8)/(x+7) is f(x)<1\lor f(x)>1