What is the inverse of 25h^2+28h-56 ?

The inverse of 25h^2+28h-56 is (-14+sqrt(25h+1596))/(25),-(sqrt(25h+1596)+14)/(25)

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inverse of 25h^2+28h-56

inverse

25 h^{2} + 28 h - 56

\frac{- 14 + 25 h + 1596}{25}, - \frac{25 h + 1596 + 14}{25}

Solution steps

y = 25 h^{2} + 28 h - 56

Replace

h

with

y

h = 25 y^{2} + 28 y - 56

Solve for

y, h = 25 y^{2} + 28 y - 56

\frac{- 14 + 25 h + 1596}{25}, - \frac{25 h + 1596 + 14}{25}

r (x) = \frac{x ( x - 18 ) ^{2}}{( x - 18 )}

(0, 4), (4, 0)

f (x) = \frac{x ^{2} + 5 x - 36}{x ^{2} - 16}

\frac{( x - 3 ) ( x + 1 )}{x + 2}

f (x) = 7 x^{3}

What is the inverse of 25h^2+28h-56 ?
The inverse of 25h^2+28h-56 is (-14+sqrt(25h+1596))/(25),-(sqrt(25h+1596)+14)/(25)