What is the inverse of h(x)=7x^{3/5} ?

The inverse of h(x)=7x^{3/5} is (x^{5/3})/(7*49^{1/3)}

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inverse of h(x)=7x^{3/5}

inverse

h (x) = 7 x^{\frac{3}{5}}

\frac{x ^{\frac{5}{3}}}{7 \cdot 4 9 ^{\frac{1}{3}}}

Solution steps

y = 7 x^{\frac{3}{5}}

Replace

x

with

y

x = 7 y^{\frac{3}{5}}

Solve for

y, x = 7 y^{\frac{3}{5}}

\frac{x ^{\frac{5}{3}}}{7 \cdot 4 9 ^{\frac{1}{3}}}

(x + 3)^{3}

f (x) = (x - 2)^{2} - 9

y = (x + 7)^{3} - 2

7 x - 9

\frac{x - 1}{x + 4}

What is the inverse of h(x)=7x^{3/5} ?
The inverse of h(x)=7x^{3/5} is (x^{5/3})/(7*49^{1/3)}