What is the asymptotes of f(x)=(x^2-36)/(10x+2) ?

The asymptotes of f(x)=(x^2-36)/(10x+2) is Vertical: x=-1/5 ,Slant: y= 1/10 x-1/50

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asymptotes of f(x)=(x^2-36)/(10x+2)

asymptotes

f (x) = \frac{x ^{2} - 36}{10 x + 2}

Vertical : x = - \frac{1}{5}, Slant : y = \frac{1}{10} x - \frac{1}{50}

Solution steps

Vertical asymptotes of

\frac{x ^{2} - 36}{10 x + 2} : x = - \frac{1}{5}

Horizontal Asymptotes of

\frac{x ^{2} - 36}{10 x + 2} :

None

Slant Asymptotes of

\frac{x ^{2} - 36}{10 x + 2} : y = \frac{1}{10} x - \frac{1}{50}

Vertical : x = - \frac{1}{5}, Slant : y = \frac{1}{10} x - \frac{1}{50}

14

y = x - 4

f (x) = - x^{5} - 3

y = 4 x + 8

x (x + 1)

What is the asymptotes of f(x)=(x^2-36)/(10x+2) ?
The asymptotes of f(x)=(x^2-36)/(10x+2) is Vertical: x=-1/5 ,Slant: y= 1/10 x-1/50