What is the perpendicular y=-2x+2,(0,1) ?

The perpendicular y=-2x+2,(0,1) is y= 1/2 x+1

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perpendicular y=-2x+2,(0,1)

perpendicular

y = - 2 x + 2, (0, 1)

y = \frac{1}{2} x + 1

Solution steps

Find the line

y = mx + b

perpendicular to

y = - 2 x + 2

that passes through

(0, 1)

Find the slope of

y = - 2 x + 2 : m = - 2

Compute the slope of the perpendicular line:

m_{p} = \frac{1}{2}

Find the line with slope m=

\frac{1}{2}

and passing through

(0, 1) : y = \frac{1}{2} x + 1

y = \frac{1}{2} x + 1

f (x) = \frac{x}{x ^{2} + 25}

f (x) = 7 x + 4

f (x) = (x + 5)^{7}

f (x) = \frac{x - 7}{x - 4}

(100, 32.5), (300, 39.5)

What is the perpendicular y=-2x+2,(0,1) ?
The perpendicular y=-2x+2,(0,1) is y= 1/2 x+1