What is the asymptotes of f(x)=(sqrt(x^2+1))/(x+1) ?

The asymptotes of f(x)=(sqrt(x^2+1))/(x+1) is Vertical: x=-1,Horizontal: y=1,y=-1

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asymptotes of f(x)=(sqrt(x^2+1))/(x+1)

asymptotes

f (x) = \frac{x ^{2} + 1}{x + 1}

Vertical : x = - 1, Horizontal : y = 1, y = - 1

Solution steps

Vertical asymptotes of

\frac{x ^{2} + 1}{x + 1} : x = - 1

Horizontal Asymptotes of

\frac{x ^{2} + 1}{x + 1} : y = 1, y = - 1

Slant Asymptotes of

\frac{x ^{2} + 1}{x + 1} :

None

Vertical : x = - 1, Horizontal : y = 1, y = - 1

y = - \frac{4}{5} x - 4

3 - x \cdot x^{2} - 1

f (x) = 10 x - 9

(\frac{1}{2})^{x + 4}

f (x) = 7.48 x + 5

What is the asymptotes of f(x)=(sqrt(x^2+1))/(x+1) ?
The asymptotes of f(x)=(sqrt(x^2+1))/(x+1) is Vertical: x=-1,Horizontal: y=1,y=-1