What is the parity (x-1)/(x^3+4x^2+12x+8) ?

The parity (x-1)/(x^3+4x^2+12x+8) is Neither even nor odd

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

parity (x-1)/(x^3+4x^2+12x+8)

parity

\frac{x - 1}{x ^{3} + 4 x ^{2} + 12 x + 8}

Neither even nor odd

Solution steps

f (- x) : \frac{- x - 1}{- x ^{3} + 4 x ^{2} - 12 x + 8}

- f (x) : - \frac{x - 1}{x ^{3} + 4 x ^{2} + 12 x + 8}

Check parity of

\frac{x - 1}{x ^{3} + 4 x ^{2} + 12 x + 8}

Check if Even:

False

Check if Odd:

False

Neither even nor odd

f (x) = \frac{sec ( π x )}{2}

2 x^{6} + x^{8} + 3

3 x

\frac{ln ( x - 1 )}{( x - 1 ) ^{3}}

y = 4 x

What is the parity (x-1)/(x^3+4x^2+12x+8) ?
The parity (x-1)/(x^3+4x^2+12x+8) is Neither even nor odd