What is the range of f(x)=-1/3 sin(3x) ?

The range of f(x)=-1/3 sin(3x) is -1/3 <= f(x)<= 1/3

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range of f(x)=-1/3 sin(3x)

range

f (x) = - \frac{1}{3} sin (3 x)

- \frac{1}{3} \leq f (x) \leq \frac{1}{3}

Interval Notation

[- \frac{1}{3}, \frac{1}{3}]

Solution steps

The range of the basic

sin

function is

- 1 \leq sin (3 x) \leq 1

- 1 \leq sin (3 x) \leq 1

Multiply the edges of the range by:

- \frac{1}{3}

- \frac{1}{3} \leq - \frac{1}{3} sin (3 x) \leq \frac{1}{3}

Therefore the range is

- \frac{1}{3} \leq f (x) \leq \frac{1}{3}

(2, - 11), (- 9, 0)

f (x) = \frac{\frac{3}{x - 2}}{x - 1}

f (x) = - 32 x - 5

f (x) = 3 + \frac{6}{x}

- x^{2} + 8 x - 10

What is the range of f(x)=-1/3 sin(3x) ?
The range of f(x)=-1/3 sin(3x) is -1/3 <= f(x)<= 1/3