What is the domain of f(x)=\sqrt[3]{x}-1 ?

The domain of f(x)=\sqrt[3]{x}-1 is -infinity <x<infinity

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of f(x)=\sqrt[3]{x}-1

domain

- \infty < x < \infty

Interval Notation

(- \infty, \infty)

Solution steps

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < x < \infty

f (x) = x^{3} + 6 x^{2} + 1

f (x) = \frac{2}{x - 1}

f (x) = \frac{1}{4 - x ^{2}}

f (x) = x^{4} - 50 x^{2} + 11

(- \frac{1}{2}, \frac{3}{4}), (\frac{7}{2}, - \frac{13}{4})

What is the domain of f(x)=\sqrt[3]{x}-1 ?
The domain of f(x)=\sqrt[3]{x}-1 is -infinity <x<infinity