What is the inverse of f(x)=(x-6)^2,x>= 6 ?

The inverse of f(x)=(x-6)^2,x>= 6 is sqrt(x)+6,-sqrt(x)+6

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inverse of f(x)=(x-6)^2,x>= 6

inverse

f (x) = (x - 6)^{2}, x \geq 6

x + 6, - x + 6

Solution steps

y = (x - 6)^{2}

Replace

x

with

y

x = (y - 6)^{2}

Solve for

y, x = (y - 6)^{2}

x + 6, - x + 6

f (x) = x x + 3

f (x) = 3 - x + 7

(6.6) (1.2)

f (x) = 3 - x \cdot x^{2} - 1

x^{4} - 5 x^{3} + x^{2} + 21 x - 18

What is the inverse of f(x)=(x-6)^2,x>= 6 ?
The inverse of f(x)=(x-6)^2,x>= 6 is sqrt(x)+6,-sqrt(x)+6