What is the domain of f(x)=sqrt(3-x)*sqrt(x^2-1) ?

The domain of f(x)=sqrt(3-x)*sqrt(x^2-1) is x<=-1\lor 1<= x<= 3

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domain of f(x)=sqrt(3-x)*sqrt(x^2-1)

domain

f (x) = 3 - x \cdot x^{2} - 1

x \leq - 1 or 1 \leq x \leq 3

Interval Notation

(- \infty, - 1] \cup [1, 3]

Solution steps

Find non-negative values for radicals:

x \leq - 1 or 1 \leq x \leq 3

The function domain

x \leq - 1 or 1 \leq x \leq 3

x^{4} - 5 x^{3} + x^{2} + 21 x - 18

f (x) = \frac{3}{5 + x}

\frac{( x + 6 ) ( x - 1 )}{( x - 1 ) ( x - 6 )}

(211, 0.6), (250, 0.48)

8 y - 3 = - 3 (4 - 2 x)

What is the domain of f(x)=sqrt(3-x)*sqrt(x^2-1) ?
The domain of f(x)=sqrt(3-x)*sqrt(x^2-1) is x<=-1\lor 1<= x<= 3