What is the critical 2xe^{-x^2} ?

The critical 2xe^{-x^2} is x=-1/(sqrt(2)),x= 1/(sqrt(2))

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critical 2xe^{-x^2}

critical points

2 x e^{- x^{2}}

x = - \frac{1}{2}, x = \frac{1}{2}

Solution steps

2 x e^{- x^{2}}

Find where

f^{'} (x)

is equal to zero or undefined

x = - \frac{1}{2}, x = \frac{1}{2}

Identify critical points not in

f (x)

domain

Domain of

2 x e^{- x^{2}} : - \infty < x < \infty

All critical points are in domain

x = - \frac{1}{2}, x = \frac{1}{2}

f (x) = x + 1 + 3

- 5 sin (29 (x - 3)) - 8

\frac{x}{x + 5}

\frac{x}{x - 5}

f (x) = \frac{x + 1}{- 2}

What is the critical 2xe^{-x^2} ?
The critical 2xe^{-x^2} is x=-1/(sqrt(2)),x= 1/(sqrt(2))