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Popular >

range of f(x)=5x^2+4x-9

Solution

range

f (x) = 5 x^{2} + 4 x - 9

Solution

f (x) \geq - \frac{49}{5}

+1

Interval Notation

[- \frac{49}{5}, \infty)

Solution steps

Vertex of

5 x^{2} + 4 x - 9 :

Minimum

(- \frac{2}{5}, - \frac{49}{5})

For a parabola

a x^{2} + b x + c

with Vertex

(x_{v}, y_{v})

If

a < 0

the range is

f (x) \leq y_{v}

If

a > 0

the range is

f (x) \geq y_{v}

a = 5,

Vertex

(x_{v}, y_{v}) = (- \frac{2}{5}, - \frac{49}{5})

f (x) \geq - \frac{49}{5}

Popular Examples

inverse of 2/(x^2+1)inverse

\frac{2}{x ^{2} + 1}

domain of x^2-2x-2 domain

x^{2} - 2 x - 2

slope of y=-1/5 x-4 slope

y = - \frac{1}{5} x - 4

extreme f(x)=(x-3)^{2/3}extreme points

f (x) = (x - 3)^{\frac{2}{3}}

domain of f(x)=((3x+8))/(x^2-81)domain

f (x) = \frac{( 3 x + 8 )}{x ^{2} - 81}

Frequently Asked Questions (FAQ)

What is the range of f(x)=5x^2+4x-9 ?
The range of f(x)=5x^2+4x-9 is f(x)>=-49/5