What is the critical 2x-3+(5x+5)/(x^2-1) ?

The critical 2x-3+(5x+5)/(x^2-1) is x=-sqrt(5/2)+1,x=sqrt(5/2)+1

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critical 2x-3+(5x+5)/(x^2-1)

critical points

2 x - 3 + \frac{5 x + 5}{x ^{2} - 1}

x = - \frac{5}{2} + 1, x = \frac{5}{2} + 1

Solution steps

2 x - 3 + \frac{5 x + 5}{x ^{2} - 1}

Find where

f^{'} (x)

is equal to zero or undefined

x = - \frac{5}{2} + 1, x = \frac{5}{2} + 1, x = 1

Identify critical points not in

f (x)

domain

Domain of

2 x - 3 + \frac{5 x + 5}{x ^{2} - 1} : x < - 1 or - 1 < x < 1 or x > 1

2 x - 3 + \frac{5 x + 5}{x ^{2} - 1}

is not defined at

x = 1

, therefore:

x = - \frac{5}{2} + 1, x = \frac{5}{2} + 1

y = arctan (x + \frac{π}{2})

f (x) = \frac{2 x ^{3}}{x ^{3} - 1}

\frac{1}{\frac{1}{x + 5} + 5}

x^{5} + 2 x^{4} - x - 2

(- 4, - 3), (8, - 9)

What is the critical 2x-3+(5x+5)/(x^2-1) ?
The critical 2x-3+(5x+5)/(x^2-1) is x=-sqrt(5/2)+1,x=sqrt(5/2)+1