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Popular >

midpoint (8,1),(-2,-5)

Solution

midpoint

(8, 1), (- 2, - 5)

Solution

(3, - 2)

Solution steps

Midpoint of

(x_{1}, y_{1}), (x_{2}, y_{2})

:

(\frac{x _{2} + x _{1}}{2}, \frac{y _{2} + y _{1}}{2})

(x_{1}, y_{1}) = (8, 1), (x_{2}, y_{2}) = (- 2, - 5)

= (\frac{- 2 + 8}{2}, \frac{- 5 + 1}{2})

Refine

= (3, - 2)

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f (x) = \frac{( 4 x ^{2} - 1 )}{∣ 2 x + 1 ∣}

domain of sqrt(x^2+16)domain

x^{2} + 16

range of f(x)= 5/(sqrt(x-9))range

f (x) = \frac{5}{x - 9}

inverse of f(x)=arcsec(x)inverse

f (x) = arcsec (x)

domain of f(x)=9-(x-2)^2 domain

f (x) = 9 - (x - 2)^{2}

Frequently Asked Questions (FAQ)

What is the midpoint (8,1),(-2,-5) ?
The midpoint (8,1),(-2,-5) is (3,-2)