What is the critical g(x)=(x^2-3)/(x+2) ?

The critical g(x)=(x^2-3)/(x+2) is x=-3,x=-1

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critical g(x)=(x^2-3)/(x+2)

critical points

g (x) = \frac{x ^{2} - 3}{x + 2}

x = - 3, x = - 1

Solution steps

\frac{x ^{2} - 3}{x + 2}

Find where

f^{'} (x)

is equal to zero or undefined

x = - 3, x = - 1, x = - 2

Identify critical points not in

f (x)

domain

Domain of

\frac{x ^{2} - 3}{x + 2} : x < - 2 or x > - 2

\frac{x ^{2} - 3}{x + 2}

is not defined at

x = - 2

, therefore:

x = - 3, x = - 1

f (x) = - x - 3

(5, 3), (- 1, - 1)

(0, 0), (3, 3)

f (x) = 2 x + y = 4

(3, - 4), (5, 6)

What is the critical g(x)=(x^2-3)/(x+2) ?
The critical g(x)=(x^2-3)/(x+2) is x=-3,x=-1