What is the domain of sqrt(x^2-2) ?

The domain of sqrt(x^2-2) is x = sqrt(2)

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domain of sqrt(x^2-2)

domain

x^{2} - 2

x \leq - 2 or x \geq 2

Interval Notation

(- \infty, - 2] \cup [2, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 2 or x \geq 2

The function domain

x \leq - 2 or x \geq 2

\frac{5 x}{x + 6}

f (x) = \frac{( x + 1 )}{x - 1}

- x^{3} + 4 x^{2} + 3 x + 4

f (x) = 4^{x} + 3

f (x) = 120 (7)^{x}

What is the domain of sqrt(x^2-2) ?
The domain of sqrt(x^2-2) is x<=-sqrt(2)\lor x>= sqrt(2)