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Popular >

distance (2,2),(4,3)

Solution

distance

(2, 2), (4, 3)

Solution

5

Solution steps

The distance between

(x_{1}, y_{1}), (x_{2}, y_{2})

is:

(x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}

The distance between

(2, 2)

and

(4, 3)

is

= (4 - 2)^{2} + (3 - 2)^{2}

Simplify

= 5

Popular Examples

intercepts of f(x)=x^2+8x+15 intercepts

f (x) = x^{2} + 8 x + 15

domain of f(x)=(sin(2x))/(1+sin(2x))domain

f (x) = \frac{sin ( 2 x )}{1 + sin ( 2 x )}

range of cos(5x)range

cos (5 x)

inverse of y=(x+1)/(x-1)inverse

y = \frac{x + 1}{x - 1}

asymptotes of (2x^2-7x-15)/(3x^2-14x-5)asymptotes

\frac{2 x ^{2} - 7 x - 15}{3 x ^{2} - 14 x - 5}

Frequently Asked Questions (FAQ)

What is the distance (2,2),(4,3) ?
The distance (2,2),(4,3) is square root of 5