What is the domain of y= x/(1-ln(x-3)) ?

The domain of y= x/(1-ln(x-3)) is 3 e+3

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domain of y= x/(1-ln(x-3))

domain

y = \frac{x}{1 - ln ( x - 3 )}

3 < x < e + 3 or x > e + 3

Interval Notation

(3, e + 3) \cup (e + 3, \infty)

Solution steps

Find positive values for logs:

x > 3

Find undefined (singularity) points:

x = e + 3

Combine real regions and undefined points for final function domain

3 < x < e + 3 or x > e + 3

\frac{x - 2}{5}

y = - \frac{3}{x + 4}

m = - \frac{4}{3} (0 - \frac{2}{5})

f (x) = (x + x + 4)

csc (x)

What is the domain of y= x/(1-ln(x-3)) ?
The domain of y= x/(1-ln(x-3)) is 3<x<e+3\lor x>e+3