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Popular >

distance (-6,2),(-1,3)

Solution

distance

(- 6, 2), (- 1, 3)

Solution

26

Solution steps

The distance between

(x_{1}, y_{1}), (x_{2}, y_{2})

is:

(x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}

The distance between

(- 6, 2)

and

(- 1, 3)

is

= (- 1 - (- 6))^{2} + (3 - 2)^{2}

Simplify

= 26

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f (x) = \frac{x + 3}{3}

inverse of f(x)=-2cos(5x)inverse

f (x) = - 2 cos (5 x)

asymptotes of (-2x-8)/(x^2+6x+8)asymptotes

\frac{- 2 x - 8}{x ^{2} + 6 x + 8}

parity f(x)=(x^3-x)/(x^2+1)parity

f (x) = \frac{x ^{3} - x}{x ^{2} + 1}

asymptotes of f(x)=(x-2)/(x^2-2x-3)asymptotes

f (x) = \frac{x - 2}{x ^{2} - 2 x - 3}

Frequently Asked Questions (FAQ)

What is the distance (-6,2),(-1,3) ?
The distance (-6,2),(-1,3) is square root of 26