What is the range of f(x)=(1/8)^x ?

The range of f(x)=(1/8)^x is f(x)>0

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range of f(x)=(1/8)^x

range

f (x) = (\frac{1}{8})^{x}

f (x) > 0

Interval Notation

(0, \infty)

Solution steps

The range of an exponential function of the form

c \cdot n^{a x + b} + k

f (x) > k

k = 0

f (x) > 0

f (x) = \frac{4}{1 - e ^{x}}

\frac{4 - x}{x ( x - 3 )}

y = - \frac{1}{4} x + 2

- \frac{1}{2 7 - x}

\frac{x - 6}{x ^{2} - 25}