What is the critical f(x)=3xe^{2x} ?

The critical f(x)=3xe^{2x} is x=-1/2

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critical f(x)=3xe^{2x}

critical points

f (x) = 3 x e^{2 x}

x = - \frac{1}{2}

Solution steps

3 x e^{2 x}

Find where

f^{'} (x)

is equal to zero or undefined

x = - \frac{1}{2}

Identify critical points not in

f (x)

domain

Domain of

3 x e^{2 x} : - \infty < x < \infty

All critical points are in domain

x = - \frac{1}{2}

f (t) = 2.3 cos (0.25 t)

f (x) = x^{2} + 4 x - 12

(5.6) (1.3)

\frac{x ( x - 5 )}{2 ( x + 3 )}

f (x) = \frac{x + 2}{x + 8}