What is the domain of (4x+7)/(6x^2+13x-5) ?

The domain of (4x+7)/(6x^2+13x-5) is x 1/3

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domain of (4x+7)/(6x^2+13x-5)

domain

\frac{4 x + 7}{6 x ^{2} + 13 x - 5}

x < - \frac{5}{2} or - \frac{5}{2} < x < \frac{1}{3} or x > \frac{1}{3}

Interval Notation

(- \infty, - \frac{5}{2}) \cup (- \frac{5}{2}, \frac{1}{3}) \cup (\frac{1}{3}, \infty)

Solution steps

Find undefined (singularity) points:

x = \frac{1}{3}, x = - \frac{5}{2}

The function domain

x < - \frac{5}{2} or - \frac{5}{2} < x < \frac{1}{3} or x > \frac{1}{3}

\frac{3 x - 5}{2 - 4 x}

f (x) = \frac{5 x + 2}{7}

f (x) = 2 x^{4}, x \geq 0

f (x) = - 4 + lo g_{2} (5 - 2 x)

3 x^{5} - 5 x^{3} - 7

What is the domain of (4x+7)/(6x^2+13x-5) ?
The domain of (4x+7)/(6x^2+13x-5) is x<-5/2 \lor-5/2 <x< 1/3 \lor x> 1/3