What is the perpendicular y= 1/8 x+2 ?

The perpendicular y= 1/8 x+2 is y=-8x+b

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perpendicular y= 1/8 x+2

perpendicular

y = \frac{1}{8} x + 2

y = - 8 x + b

Solution steps

Find the slope of

y = \frac{1}{8} x + 2 : m = \frac{1}{8}

Compute the slope of the perpendicular line:

m_{p} = - 8

Line with slope m=

- 8 : y = - 8 x + b

y = - 8 x + b

f (x) = 3 x^{2} - 12 x + 8

(0, 0), (8, 2)

7 x^{4}

f (x) = - x^{2} + 18 x - 79

(2 - x^{3})^{5}