What is the inverse of f(x)=sqrt(x^2-8x) ?

The inverse of f(x)=sqrt(x^2-8x) is 4+sqrt(x^2+16),4-sqrt(x^2+16)

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inverse of f(x)=sqrt(x^2-8x)

inverse

f (x) = x^{2} - 8 x

4 + x^{2} + 16, 4 - x^{2} + 16

Solution steps

y = x^{2} - 8 x

Replace

x

with

y

x = y^{2} - 8 y

Solve for

y, x = y^{2} - 8 y

4 + x^{2} + 16, 4 - x^{2} + 16

f (x) = \frac{5}{2 - x}, x < 2

y = - \frac{5}{2} x + 6

4 x^{3} - 33 x^{2} + 84 x - 60

y = \frac{1}{4} x - 4

f (x) = (e^{(- 5 x - \frac{1}{2})} + 5)

What is the inverse of f(x)=sqrt(x^2-8x) ?
The inverse of f(x)=sqrt(x^2-8x) is 4+sqrt(x^2+16),4-sqrt(x^2+16)