What is the inverse of sqrt(38)(e^t-1) ?

The inverse of sqrt(38)(e^t-1) is ln((sqrt(38)t)/(38)+1)

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inverse of sqrt(38)(e^t-1)

inverse

38 (e^{t} - 1)

ln (\frac{38 t}{38} + 1)

Solution steps

y = 38 (e^{t} - 1)

Replace

t

with

y

t = 38 (e^{y} - 1)

Solve for

y, t = 38 (e^{y} - 1)

ln (\frac{38 t}{38} + 1)

f (x) = (\frac{( 2 x - 1 )}{( x - 3 )})

f (x) = 2 x^{2}

\frac{3 x + 15}{5 x}

2 x^{3} + 5

f (x) = - 3 x^{4} + 18 x^{2}

What is the inverse of sqrt(38)(e^t-1) ?
The inverse of sqrt(38)(e^t-1) is ln((sqrt(38)t)/(38)+1)