What is the perpendicular y= 1/5 x+4/5 ,(1,1) ?

The perpendicular y= 1/5 x+4/5 ,(1,1) is y=-5x+6

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perpendicular y= 1/5 x+4/5 ,(1,1)

perpendicular

y = \frac{1}{5} x + \frac{4}{5}, (1, 1)

y = - 5 x + 6

Solution steps

Find the line

y = mx + b

perpendicular to

y = \frac{1}{5} x + \frac{4}{5}

that passes through

(1, 1)

Find the slope of

y = \frac{1}{5} x + \frac{4}{5} : m = \frac{1}{5}

Compute the slope of the perpendicular line:

m_{p} = - 5

Find the line with slope m=

- 5

and passing through

(1, 1) : y = - 5 x + 6

y = - 5 x + 6

f (x) = 25 - t^{2}

f (t) = \frac{56}{( t + 7 ) ^{2}}

f (x) = \frac{x + 1}{x + 3}

17

x^{8} (x - 2)^{7}

What is the perpendicular y= 1/5 x+4/5 ,(1,1) ?
The perpendicular y= 1/5 x+4/5 ,(1,1) is y=-5x+6