What is the domain of x/(\sqrt[3]{x^2-4)} ?

The domain of x/(\sqrt[3]{x^2-4)} is x 2

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domain of x/(\sqrt[3]{x^2-4)}

domain

x < - 2 or - 2 < x < 2 or x > 2

Interval Notation

(- \infty, - 2) \cup (- 2, 2) \cup (2, \infty)

Solution steps

Find undefined (singularity) points:

x = 2, x = - 2

The function domain

x < - 2 or - 2 < x < 2 or x > 2

f (x) = 5 x

(34, 269), (356, 99)

f (x) = \frac{1}{x} - 2

f (x) = \frac{3 x - 9}{8}

y = 5 + \frac{25}{x}

What is the domain of x/(\sqrt[3]{x^2-4)} ?
The domain of x/(\sqrt[3]{x^2-4)} is x<-2\lor-2<x<2\lor x>2