What is the domain of f(x)=sqrt(x^2-64) ?

The domain of f(x)=sqrt(x^2-64) is x = 8

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domain of f(x)=sqrt(x^2-64)

domain

f (x) = x^{2} - 64

x \leq - 8 or x \geq 8

Interval Notation

(- \infty, - 8] \cup [8, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 8 or x \geq 8

The function domain

x \leq - 8 or x \geq 8

x - 5^{2}

y = 9 - x^{2}

3^{- x}

y = - x + 7

What is the domain of f(x)=sqrt(x^2-64) ?
The domain of f(x)=sqrt(x^2-64) is x<=-8\lor x>= 8