What is the domain of (sqrt(x+3))/(-2x+8) ?

The domain of (sqrt(x+3))/(-2x+8) is -3 4

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domain of (sqrt(x+3))/(-2x+8)

domain

\frac{x + 3}{- 2 x + 8}

- 3 \leq x < 4 or x > 4

Interval Notation

[- 3, 4) \cup (4, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - 3

Find undefined (singularity) points:

x = 4

Combine real regions and undefined points for final function domain

- 3 \leq x < 4 or x > 4

e^{- y} + e^{2}

\frac{x + 9}{x ^{2} - 81}

f (x) = \frac{x ^{2}}{x ^{2} - x - 30}

f (x) = - 5 x + 1

f (x) = \frac{x + 5}{x - 5}

What is the domain of (sqrt(x+3))/(-2x+8) ?
The domain of (sqrt(x+3))/(-2x+8) is -3<= x<4\lor x>4