What is the domain of (2x^2+8x-24)/(x^2+x-12) ?

The domain of (2x^2+8x-24)/(x^2+x-12) is x 3

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domain of (2x^2+8x-24)/(x^2+x-12)

domain

\frac{2 x ^{2} + 8 x - 24}{x ^{2} + x - 12}

x < - 4 or - 4 < x < 3 or x > 3

Interval Notation

(- \infty, - 4) \cup (- 4, 3) \cup (3, \infty)

Solution steps

Find undefined (singularity) points:

x = 3, x = - 4

The function domain

x < - 4 or - 4 < x < 3 or x > 3

f (x) = \frac{12}{x} - 18

f (x) = \frac{1}{x ^{2} - 1}

f (x) = 2 x^{3} - 6 x^{2} + 30

\frac{1}{9} x^{4} - \frac{4}{9} x^{3}

g (x) = \frac{1}{x} - 1

What is the domain of (2x^2+8x-24)/(x^2+x-12) ?
The domain of (2x^2+8x-24)/(x^2+x-12) is x<-4\lor-4<x<3\lor x>3