What is the domain of y=f(x)=xsqrt(4-x^2) ?

The domain of y=f(x)=xsqrt(4-x^2) is -2<= x<= 2

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domain of y=f(x)=xsqrt(4-x^2)

domain

y = f (x) = x 4 - x^{2}

- 2 \leq x \leq 2

Interval Notation

[- 2, 2]

Solution steps

Find non-negative values for radicals:

- 2 \leq x \leq 2

The function domain

- 2 \leq x \leq 2

f (x) = - x^{2} + 10

f (x) = 2^{1 0^{x}}

f (x) = \frac{2 x ^{2} - x - 9}{x ^{2} + 1}

1.6 x + 7.25

f (x) = \frac{2 x + 1}{x ^{2} + x - 2}

What is the domain of y=f(x)=xsqrt(4-x^2) ?
The domain of y=f(x)=xsqrt(4-x^2) is -2<= x<= 2